閱讀快車系列答案科目：小學數學 來源： 題型：
| 0.02×0.1= | 5.06x-4.07x= | 12-7.8= | a+0.4a= |
| 12÷0.3= | 4.6x+2.7x= | 1.7+0.43= | 0.58a-0.47a= |
| 1.5×0.4= | 4.8x-3.1x= | 1.25×0.2= | 12a-8.4a= |
| 64.32÷16= | 6x-4.9x= | 5.1b+11.9b= | 1.23÷3= |
| 100×0.01= | 3.4×0.07= | 3x+4x= | 0.42÷0.1= |
| 4.3b-2.7b= | 7÷0.25= | 5.1x+2.9x= | 1.75×0.8= |
| 0.3×0.4= | 5.4+1.4= | 2.7x+3.6x= | 16÷1.6= |
| 10x-3.7x= | 0.98+1.82= | 2.5x+4.3x= | 0.05×0.8= |
| 6.05x-4.96x= | 3.7a+5.2a= | 3.2÷1.6= | 3.12÷0.5= |
| 3.5+7.6= | 5.1a+3.9a= | 10×0.75= | 3b-0.7b= |
| 5.6×0.1= | x×x= | 0.9÷0.01= | 3.4b+5.6b= |
| 72.8÷0.8= | 2.7b+5b= | 3.5×3= | 7.6b-4.3b= |
| 32= | 2.52= | 4x+5x= | 3.5t-t= |
| 8a-3a= | 7b+b= | 4c-2c= | 3.5b+2.7b= |
| 0.32÷0.04= | 0.51×0.2= | 0.12+3.4= | 102= |
查看答案和解析>>
湖北省互聯網違法和不良信息舉報平臺 | 網上有害信息舉報專區 | 電信詐騙舉報專區 | 涉歷史虛無主義有害信息舉報專區 | 涉企侵權舉報專區
違法和不良信息舉報電話：027-86699610 舉報郵箱：58377363@163.com