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A. B. C. D. 【查看更多】

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從A,B,C,D四個(gè)選項(xiàng)中，找出其劃線部分與所給單詞的劃線部分讀音相同的選項(xiàng)。

polite A．possible B．climate C．province D．terrible

houses A．potatoes B．teaches C．knives D．cakes

piece A．believe B．friendly C．tie D．society

social A．cinema B．percent C．bicycle D．a(chǎn)ncient

repair A．culture B．inspire C．compare D．heart

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從A,B,C,D四個(gè)選項(xiàng)中，選出其畫線部分與所給單詞的畫線部分讀音相同的選項(xiàng)，并將答案寫在答題卡上。

bother A. faith B. method C northern D. threat

bow A. sow B. shower C. flow D. grown

prove A. nod B. plot C. remove D. roll

surface A .discovery B. condition C. special D.certain

speech A．church B．stomach C．technology D．machine

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從A B C D中找出其劃線部分與所給單詞劃線部分讀音相同的項(xiàng)

satisfy A. branch B. engage C. graduate D. around

expedition A. exist B. Exercise C. expense D. explore

whole A. where B. which C. why D. who

chemical A. church B. child C. chips D. Christmas

south A. courage B. soup C. southern D. trousers

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從A,B,C,D四個(gè)選項(xiàng)中，找出其劃線部分與所給單詞的劃線部分讀音相同的選項(xiàng)，并在答題卡上將該項(xiàng)涂黑。
【小題1】idea

A．mean

B．pleasant

C．healthy

D．a(chǎn)rea

【小題2】promise

A．shock

B．provide

C．remove

D．moment

【小題3】exist

A．exercise

B．explore

C．examine

D．expression

【小題4】position

A．persuade

B．a(chǎn)dvise

C．nervous

D．increase

【小題5】society

A．a(chǎn)chieve

B．friend

C．science

D．believe

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1．解析：，故選A。

2．解析：∵

，

故選B。

3．解析：由，得，此時(shí)，所以，，故選C。

4．解析：顯然，若與共線，則與共線；若與共線，則，即，得，∴與共線，∴與共線是與共線的充要條件，故選C。

5．解析：設(shè)公差為，由題意得，；，解得或，故選C。

6．解析：∵雙曲線的右焦點(diǎn)到一條漸近線的距離等于焦距的，∴，又∵，∴，∴，∴雙曲線的離心率是。故選B.

7.解析：∵、為正實(shí)數(shù)，∴，∴；由均值不等式得恒成立，，故②不恒成立，又因?yàn)楹瘮?shù)在是增函數(shù)，∴，故恒成立的不等式是①③④。故選C.

8．解析：∵，∴在區(qū)間上恒成立，即在區(qū)間上恒成立，∴，故選D。

9．解析：∵

，此函數(shù)的最小值為，故選C。

10．解析：如圖，∵正三角形的邊長為，∴，∴，又∵，∴，故選D。

11．解析：∵在區(qū)間上是增函數(shù)且，∴其反函數(shù)在區(qū)間上是增函數(shù)，∴，故選A

12．解析：如圖，①當(dāng)或時(shí)，圓面被分成2塊，涂色方法有20種；②當(dāng)或時(shí)，圓面被分成3塊，涂色方法有60種；

③當(dāng)時(shí)，圓面被分成4塊，涂色方法有120種，所以m的取值范圍是，故選A。

13．解析：做出表示的平面區(qū)域如圖，當(dāng)直線經(jīng)過點(diǎn)時(shí)，取得最大值5。

學(xué)科網(wǎng)(Zxxk.Com) 14.解析：∵，∴時(shí)，，又時(shí)，滿足上式，因此，，

∴。

學(xué)科網(wǎng)(Zxxk.Com) 15．解析：設(shè)正四面體的棱長為，連，取的中點(diǎn)，連，∵為的中點(diǎn)，∴∥，∴或其補(bǔ)角為與所成角，∵，，∴，∴，又∵，∴，∴與所成角的余弦值為。

學(xué)科網(wǎng)(Zxxk.Com) 16．解析：∵，∴，∵點(diǎn)為的準(zhǔn)線與軸的交點(diǎn)，由向量的加法法則及拋物線的對(duì)稱性可知，點(diǎn)為拋物線上關(guān)于軸對(duì)稱的兩點(diǎn)且做出圖形如右圖，其中為點(diǎn)到準(zhǔn)線的距離，四邊形為菱形，∴，∴，∴，∴，∴，∴向量與的夾角為。