Question

若a,b,c＞0且a(a+b+c)+bc=4-2,則2a+b+c的最小值為(    )

A.-1             B.+1               C.2+2               D.2-2

Answer 1

解析：由a(a+b+c)+bc=,得

(a+c)(a+b)=.

∵a,b,c＞0,∴(a+c)(a+b)≤()²,

當(dāng)且僅當(dāng)a+c=b+a,即b=c時取“=”.

∴2a+b+c≥.

答案：D