Question

（8分）某手機專營店代理銷售A、B兩種型號手機．手機的進價、售價如下表：

型  號	A	B
進  價	1200元/部	1000元/部
售  價	1380元/部	1200元/部

 

 

 

 

（1）第一季度：用36000元購進 A、B兩種型號的手機，全部售完后獲利6300元，求第一季度購進A、B兩種型號手機的數量；

1.（2）第二季度：計劃購進A、B兩種型號手機共34部，且不超出第一季度的購機總費用，則A型號手機最多能購多少部？

 

Answer 1

 

1.（1）解：設該專營店第一季度購進A、B兩種型號手機的數量分別為x部和y部．····· 1分

由題意可知： ·········································································· 3分

       解得：

答：該專營店本次購進A、B兩種型號手機的數分別為15部和18部．··························· 4分

 

2.（2）解：設第二季度購進A型號手機a部．······························································· 5分

由題意可知：1200a+1000(34－a)≤36000，··································································· 6分

解得：a≤10·················································································································· 7分

不等式的最大整數解為10

答：第二季度最多能購A型號手機10部．····································································· 8分

 

解析:略